# What is the frequency of f(theta)= sin 6 t - cos 4 t ?

$\pi \mathmr{and} {180}^{\circ}$
The period (frequency) of $f \left(t 1\right) = \sin 6 t$ is $\frac{2 \pi}{6} = \frac{\pi}{3}$ or ${60}^{\circ}$
The period of $f \left(t 2\right) = \cos 4 t$ is $\frac{2 \pi}{4} = \frac{\pi}{2}$ or ${90}^{\circ}$
It is $\pi$ or ${180}^{\circ} .$