# What is the ground-state electron configuration of a neutral atom of manganese?

A quick glance at the Periodic Table tells me $Z = 25$....and we merely follow the $\text{aufbau principle.....}$
$M n , Z = 25$, $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{5}$....
And we could abbreviate this to....$\left[A r\right] 4 {s}^{2} 3 {d}^{5}$.... Agree?