# What is the hybridization at the two central carbon atoms of 2-butene?

Oct 19, 2015

$S {P}^{2}$ hybridisation

#### Explanation:

The molecular formula for 2- butene can be written as

$C {H}_{3} - C H = C H - C {H}_{3}$

count the carbon from left to right increasing order

First and fourth carbon formed covalent bond with three hydrogen and a carbon atom. In these positions carbon has undergone by $S {P}^{3}$ hybridsation giving 4 hybrid orbital, hence forming four sigma bonds

Second and third (central carbon) carbon has three sigma bonds (two hydrogen and carbon) and one pi bond. Three sigma bonds are formed due to $S {P}^{2}$ hybridization. Pz orbital from each central carbon atom under go lateral over lap giving rise a pi bond between second and third carbon atom