# What is the hybridization of the central iodine atom in I3−?

## Express your answer in the orbital notations s, p, d, and f.

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Dec 9, 2016

$s {p}^{3} d$

#### Explanation:

The easiest way to determine this is to draw the lewis structure of the species. What's important here is knowing that the species, $I$ can become hypervalent, or that is, it will disobey the octet rule by expanding its valency to accept more than eight electron around it.

Another good example of a species which does this is $X e {F}_{4}$.

Consider below:

Remember when forming hybrid orbitals, we always know that we must:

use $n$ atomic orbital to make $n$ hybrid orbitals

and

for $n = 5$ we know that we make $s {p}^{3} d$ hybrids.

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