What is the indefinite integral of the following?

Question

#root8 x^9 + dx#

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Answer 1 · 2017-11-30T01:25:15

Please see below.

#root(8)x^9 = x^(9/8)#

And #9/8+1 = 17/8#.

So,

#int root(8)x^9 dx = int x^(9/8) dx#

# = (8 x^(17/8))/17 + C#

Check the answer by differentiating and rewrite algebraically to taste.