# What is the integral of int f(x)=e^(3x) from 0 to 2?

$\frac{{e}^{6} - 1}{3}$
${\int}_{0}^{2} f \left(x\right)$
$= {\int}_{0}^{2} {e}^{3 x}$
$= {\left[\frac{{e}^{3 x}}{3}\right]}_{0}^{2}$
$= \left[\left({e}^{3 \cdot 2} / 3\right) - \left({e}^{3 \cdot 0} / 3\right)\right]$
$= \frac{{e}^{6} - 1}{3}$