Question

What is the integral of sinh(3x)-cosh(4x)dx?

Answer 1

The answer is `=1/3cosh(3x)-1/4sinh(4x)+C`

Explanation:

We need

`intsinhxdx=coshx+C`

`intcoshxdx=sinhx+C`

Therefore,

`int(sinh(3x)-cosh(4x))dx=intsinh(3x)dx-intcosh(4x)dx`

`=1/3cosh(3x)-1/4sinh(4x)+C`