What is the integral of #(x^2)(lnx)#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

3
Apr 6, 2018

Answer:

#int x^2*Lnx*dx=x^3/3*Lnx-x^3/9+C#

Explanation:

After setting #dv=x^2*dx# and #u=Lnx# for using integration by parts, #v=x^3/3# and #du=dx/x#

Hence,

#int udv=uv-int vdu#

#int x^2*Lnx*dx=x^3/3*Lnx-int x^3/3*dx/x#

=#x^3/3*Lnx-int x^2/3*dx#

=#x^3/3*Lnx-x^3/9+C#

Was this helpful? Let the contributor know!
1500