# What is the internal angle sum of a hexagon?

Mar 16, 2018

${720}^{\circ}$

#### Explanation:

First, we split the hexagon into 6 equal isoceles triangles, each have the angles ($60 , \theta , \theta$) ($\frac{360}{6} = 60$).

$\theta = \frac{180 - 60}{2} = \frac{120}{2} = 60$

$\text{Sum of internal angles} = 6 \left(120\right) = {720}^{\circ}$

May 23, 2018

${720}^{0}$

#### Explanation:

The internal sum of four triangles is $4 \times {180}^{0}$

Jun 1, 2018

Or, it can be directly calculated using direct formula,

$\rightarrow \left(n - 2\right) \cdot {180}^{\circ}$ where $n$ is the number of sides of polygon.

In case of hexagon, $n = 6$

So, internal angles sum$= \left(6 - 2\right) \cdot {180}^{\circ} = 4 \cdot {180}^{\circ} = {540}^{\circ}$