What is the inverse function of #h(x)=-2/3x+6#?

1 Answer
EZ as pi
Nov 18, 2016

#h^-1(x) =(3(6-x))/2#

Explanation:

Finding the inverse function means writing the reverse procedure of a function ...
In a function, you start with an #x# value and you calculate the #y#.

In an inverse function, you show how a #y# can be linked back to the #x#

#h(x) = -2/3x+6#

#y = -2/3x+6" "larr# step 1: make #h(x) = y#

#x = -2/3y +6" "larr#step 2: swop #x and y #

#2/3y=6-x" "larr #step 3: re-arrange to make #y =....#

#y = (3(6-x))/2#

#h^-1(x) =(3(6-x))/2" "larr# step 4: this is the inverse function

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