Question

What is the inverse function of `h(x)=log_2(x)`?

Answer 1

Inverse function of `h(x)=log_2 x` is `g(x)=2^x`

Explanation:

Let `y=log_2 x`

Hence `2^y=x`

Hence inverse function of `h(x)=log_2 x` is `g(x)=2^x`