What is the largest value of a for which the circle x^2+y^2=a^2 lies completely inside the parabola y^2=4(x+4) ?
1 Answer
Jan 28, 2018
Explanation:
Let's work this out. We have
So then when the circle intersects the parabola the values of
We now find the positive value of
(Middle coefficient)^2-(4×(product of other coefficients))=0