What is the LCD of and #5/(12b^2)# and #3/(8ab)#?

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Answer 1 · 2017-06-13T14:06:25

See a solution process below:

The first denominator can be factored as:

#12b^2 = color(red)(2) * color(red)(2) * 3 * color(red)(b) * b#

The second denominator can be factored as:

#8ab = color(red)(2) * color(red)(2) * 2 * a * color(red)(b)#

Now, we need to multiply each term by what it is missing from the other term:

#12b^2# is missing a #2# and an #a# from the other denominator:

#12b^2 * 2a = 24ab^2#

#8ab# is missing a #3# and a #b# from the other denominator:

#8ab * 3b = 24ab^2#

The LCD is #24ab^2#