What is the LCM of 6and 4?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

1
Feb 14, 2018

$12$

Explanation:

$6$ and $4$ have a common factor so their LCM will not be their product,

The prime factor method works for numbers of any size;

$\text{ } 4 = 2 \times 2$
" "6 =ul(2" "xx3)
$L C M = 2 \times 2 \times 3 = 12$

FOr small numbers you should be able to do this mentally.

Run through the multiples of the bigger number until you find one which is divisible by the other number.

$6 \text{ } \leftarrow$ no, not divisible by $4$
$12 \text{ } \leftarrow$ yes, is divisible by $4$

There are many common factors of $4 \mathmr{and} 6$, but $12$ is the lowest.

$12 , 24 , 36 , 48 , 60 \ldots \ldots$
$\uparrow$
$L C M$

Then teach the underlying concepts
Don't copy without citing sources
preview
?

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

1
sjc Share
Feb 9, 2018

$\lcm \left(4 , 6\right) = 12$

Explanation:

write down the multiples of each number then pick out the common ones

multiples of $\text{ } 4 : \left\{4 , 8 , \textcolor{red}{12} , 16 , \textcolor{red}{24} , \ldots .\right\}$

multiples of $\text{ } 6 : \left\{6 , \textcolor{red}{12} , 18 , \textcolor{red}{24} , 30 , \ldots\right\}$

common multiples$\text{ } \left\{12 , 24 , . .\right\}$

$\lcm \left(4 , 6\right) = 12$

Then teach the underlying concepts
Don't copy without citing sources
preview
?

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

1
Dwight Share
Feb 8, 2018

The LCM is 12, but how you can find it for any numbers is explained below.

Explanation:

Two find the LCM of two numbers (or more) write the numbers as the product of their prime factors. That means find a way to express the number as the product of prime numbers only (like 2, 3, 5, 7, 11 and so on).

4 can be written $2 \times 2$

6 is $2 \times 3$

Now look for any prime number that appears in both expressions (the 2 in this case).

Keep one of these 2s and all the other numbers (the other 2 in the $2 \times 2$ product and the 3 in the $2 \times 3$ product).

Multiply them all together:

$2 \times 2 \times 3 = 12$ that is the LCM!

• 11 minutes ago
• 11 minutes ago
• 12 minutes ago
• 13 minutes ago
• 5 seconds ago
• 40 seconds ago
• A minute ago
• 3 minutes ago
• 9 minutes ago
• 11 minutes ago
• 11 minutes ago
• 11 minutes ago
• 12 minutes ago
• 13 minutes ago