What is the line containing the points (0, 4) and (3, -2)?

1 Answer
Dec 14, 2016

#y - 4 = -2x# or #y = -2x + 4#

Explanation:

To find the line containing these two points we must first determine the slope.

The slope can be found by using the formula: #color(red)(m = (y_2 = y_1)/(x_2 - x_1)#
Where #m# is the slope and #(x_1, y_1)# and #(x_2, y_2)# are the two points.

Substituting our two points gives:

#m = (-2 - 4)/(3 - 0)#

#m = (-6)/3#

#m = -2#

Next we can use the point-slope formula to find the equation for the line passing through the two points.

The point-slope formula states: #color(red)((y - y_1) = m(x - x_1))#
Where #m# is the slope and #(x_1, y_1) is a point the line passes through.

Substituting #-2# for #m# and (0, 4) for the point gives:

#y - 4 = -2(x - 0)#

#y - 4 = -2x#

Now, solving for #y# to put the equation in the slope-intercept format gives:

#y - 4 + 4 = -2x + 4#

#y - 0 = -2x + 4#

#y = -2x + 4#