What is the line of symmetry of the parabola defined by y = –2(x + 4)^2 + 6?

Mar 18, 2016

x = -4

Explanation:

The quadratic function in vertex form is

$y = a {\left(x - h\right)}^{2} + k \text{where (h,k) are coords of vertex }$

The function $y = - 2 {\left(x + 4\right)}^{2} + 6 \text{ is in this form }$

and by comparison of them (-4 , 6 ) is the vertex

Now , the axis of symmetry passes through the vertex and has equation x = -4

Here is the graph of the function with line of symmetry.
graph{(y+2(x+4)^2-6)(0.001y-x-4)=0 [-12.32, 12.32, -6.16, 6.16]}