Question

What is the line of symmetry of the parabola defined by `y = –2(x + 4)^2 + 6`?

Answer 1

x = -4

Explanation:

The quadratic function in vertex form is

`y = a(x - h )^2 + k"where (h,k) are coords of vertex "`

The function `y = -2(x+4)^2 + 6" is in this form "`

and by comparison of them (-4 , 6 ) is the vertex

Now , the axis of symmetry passes through the vertex and has equation x = -4

Here is the graph of the function with line of symmetry.
graph{(y+2(x+4)^2-6)(0.001y-x-4)=0 [-12.32, 12.32, -6.16, 6.16]}