Question

What is the maximum height of a ball thrown 10 m/s upward?

Answer 1

`5.097\ m`

Explanation:

At the maximum height `h`, the final velocity of ball `v` becomes zero when thrown with an initial upward velocity `u=10\ m/s` against the gravitational acceleration `g=9.81\ m/s^2`

From, third equation of motion, we have

`v^2=u^2+2as`

setting `v=0, u=10, a=-9.81` & `s=h` as follows

`0^2=10^2-2\cdot 9.81 h`

`h=\frac{100}{19.62 }`

`=5.097\ m`