Question

What is the maximum value of `f(x) = -3x^2-6x`?

Answer 1

x = -1 is the local maximum

Explanation:

`f(x) = -3x^2 - 6x`

`f'(x) = -6x -6`

Equating to 0, we get `x = -1`

`f"(x) = -6`

It is less than 0 (negative), hence -1 is the local maximum.