# What is the molar mass of H_2CO_3?

##### 1 Answer
Mar 11, 2016

It is 62.03 $\frac{g}{m o l}$.

#### Explanation:

To find molar mass, multiply the molar mass of each atom by the number of that type of atom and then add the masses. I have done it in detail here showing units.

The molar mass is the mass in grams of 1 mol of a substance. ${H}_{2} C {O}_{3}$ has 2 atoms of H, 1 atom of C, and 3 atoms of O. So 1 mole of it has 2 mol H, 1 mol C, and 3 mol O. The mass of one mole of an atom is the molar mass in $\frac{g}{m o l}$ on the periodic table. So the molar mass is:

$2$ $m o l$ $H \cdot \frac{1.01 \setminus g \setminus H}{m o l \setminus {H}_{2} C {O}_{3}} = \frac{2.02 \setminus g \setminus H}{m o l \setminus {H}_{2} C {O}_{3}}$

$1$ $m o l$ $C \cdot \frac{12.01 \setminus g \setminus C}{m o l \setminus {H}_{2} C {O}_{3}} = \frac{12.01 \setminus g \setminus C}{m o l \setminus {H}_{2} C {O}_{3}}$

$3$ $m o l$ $O \cdot \frac{16.00 \setminus g \setminus O}{m o l \setminus {H}_{2} C {O}_{3}} = \frac{48.00 \setminus g \setminus O}{m o l \setminus {H}_{2} C {O}_{3}}$

$\frac{2.02 \setminus g \setminus H}{m o l \setminus {H}_{2} C {O}_{3}} + \frac{12.01 \setminus g \setminus C}{m o l \setminus {H}_{2} C {O}_{3}} + \frac{48.00 \setminus g \setminus O}{m o l \setminus {H}_{2} C {O}_{3}} = \frac{62.03 \setminus g \setminus {H}_{2} C {O}_{3}}{m o l \setminus {H}_{2} C {O}_{3}}$