What is the molarity of .060 mol of #NaHCO_3# in 1500 mL of solution?
In order to find molarity, you would first determine the number of moles of solute that are present, followed by the volume of solution (must be in liters). We already have the number of moles, so we just have to go from milliliters of solution to liters of solution. We do this by using the conversion factor: 1000 mL = 1 L. When you divide the 1500 mL that you're given by 1000 mL/L you obtain 1.5 L.
Afterwards, you would simply divide the two like so:
Molarity = moles of solute / liter of solution
0.060 mol NaHCO3 / 1.5 L of solution = 0.040 M.
I hope this explanation makes sense.