Question

What is the molarity of .289 moles of `FeCl_3` dissolved in 120 mL of solution?

Answer 1

Molarity=`(2.41"mol")/L`

Explanation:

Molarity=`"Moles of solute"/"Liters of solution"`

Moles=`0.289`

Solution=`120mL=0.12L`

Therefore,

Molarity=`(0.289 "mol")/(0.12 L)~~(2.41 "mol")/L`