Question

What is the molarity of 40.0 grams of sodium hydroxide in 1.50 L of solution?

Answer 1

`"Molarity"` `=` `"Amount of substance (in moles)"/"Volume of solution (in litres)"`

Explanation:

So, `(40.0*cancelg)/(40*cancelg*mol^-1)/(1.50*L)` `=` `0.667` `mol*L^-1` with respect to sodium hydroxide.