# What is the molarity of a sodium chloride solution that contains 3 moles of NaCl in 4 liters of solution?

Feb 14, 2016

"Molarity" = ("Moles of solute")/("Volume of SOLUTION").

And we get an answer with units, $m o l \cdot {L}^{-} 1$

#### Explanation:

So all we need to do is to set up this quotient. You have been given the amount of solute in moles, and the volume of solution.

So, $\text{Molarity} = \frac{3 \cdot m o l}{4 \cdot L}$ $=$ ?? mol*L^-1?

In $1$ $L$ of this solution, what is the mass of the $N a C l$ solute?