# What is the molarity of a solution containing 4.0 moles of NaOH in 2.0 L of solution?

Jan 9, 2016

$M = 2.0$ $m o l$ ${L}^{-} 1$

#### Explanation:

The molarity, $M$ of this solution can be calculated by a formula which is;

$M = \frac{n}{V}$

where;
$M$= Molarity of solution
$n$=Number of moles of solute
$V$= Volume of solution in Litre

Given, $n = 4.0$ moles and $V = 2.0$ L, so we have enough information to calculate the molarity of the solution;

$M = \frac{n}{V}$

$M = \frac{4.0}{2.0}$ $m o l$ ${L}^{-} 1$

$M = 2.0$ $m o l$ ${L}^{-} 1$ or $M = 2.0$ $m o l$ ${\mathrm{dm}}^{-} 3$ if the questions mention volume of solution in ${\mathrm{dm}}^{3}$ because $L = {\mathrm{dm}}^{3}$