What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M #NH_4Cl# solution to 2.00 L?
0.09475 moles per litre.
How many moles of solute did you start with?
Where M is molarity in moles/litre, n is number of moles, and V is number of litres.
Rearrange for n:
After diluting, how many moles of solute will you have? Answer: The same. But now the solution volume will be 2 litres.
And if you want to make it even simpler - you are diluting 50 ml to 2000 ml, which is a dilution of 40 times.
So simply divide your starting molarity by 40. 3.79 divided by 40 is 0.09475.