# What is the molarity of a solution that contains 8 g of CaCl_2 in 400 mL of water?

$\text{Concentration"="Moles of solute"/"Volume of solution}$
$\text{Concentration } = \frac{8.0 \cdot \cancel{g}}{110.98 \cdot \cancel{g} \cdot m o {l}^{-} 1} \times \frac{1}{0.400 \cdot L}$ $=$ $0.180 \cdot m o l \cdot {L}^{-} 1$ with respect to calcium chloride.