# What is the molarity of a solution with 73 g of HCl in 319 mL of solution?

Approx. $6.5 \cdot m o l \cdot {L}^{-} 1$ with respect to hydrochloric acid.
$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$=$ $\frac{73 \cdot g}{35.45 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{0.319 \cdot L}$ $=$ ??*mol*L^-1.