# What is the molarity of an aqueous solution of sodium hydroxide produced when 35.0 ml of a 5.40 M solution was diluted to 890.0 ml?

Approx. $0.2 \cdot m o l \cdot {L}^{-} 1$.
$\text{Concentration}$ $=$ $\text{Moles"/"Volume of solution}$.
And thus, $\text{Concentration}$ $=$ $\frac{35.0 \times {10}^{-} 3 L \times 5.40 \cdot m o l \cdot {L}^{-} 1}{890.0 \times {10}^{-} 3 L}$ $\cong$ $0.2 \cdot m o l \cdot {L}^{-} 1$