# What is the molarity of an H_2SO_4 solution if 0.25 liter of the solution contains 0.75 mole of H_2SO_4?

Jun 12, 2016

The solution will have a concentration of $\text{3 M}$ sulfuric acid.

#### Explanation:

The molarity, M, of a solution is determined by dividing the number of moles by the volume in liters.

$M = \frac{n}{V}$, where $\text{M}$ is the molarity, $n$ is the moles of solute, and $V$ is the volume of the solution in liters.

Substitute the given values into the molarity equation and solve.

M=(0.75"mol")/(0.25"L")="3.0 M H"_2"SO"_4, pronounced three molar sulfuric acid.