What is the molarity of an #H_2SO_4# solution if 0.25 liter of the solution contains 0.75 mole of #H_2SO_4#?

1 Answer
Jun 12, 2016

Answer:

The solution will have a concentration of #"3 M"# sulfuric acid.

Explanation:

The molarity, M, of a solution is determined by dividing the number of moles by the volume in liters.

#M=n/V#, where #"M"# is the molarity, #n# is the moles of solute, and #V# is the volume of the solution in liters.

Substitute the given values into the molarity equation and solve.

#M=(0.75"mol")/(0.25"L")="3.0 M H"_2"SO"_4#, pronounced three molar sulfuric acid.