What is the mole fraction of hydrogen in a gaseeous mixture that consist of 8.0g hydrogen and 12.0g neon in a 3.50L container maintained at 35.20 deg c?

1 Answer
anor277
May 29, 2018

#chi_(H_2)=0.871#

Explanation:

#chi_(H_2)=n_(H_2)/(n_(H_2)+n_(Ne))#

#chi_(H_2)=((8.0*g)/(2.0*g*mol^-1))/((8.0*g)/(2.0*g*mol^-1)+(12.0*g)/(20.2*g*mol^-1))=0.871#....

#chi_(Ne)=((12.0*g)/(20.2*g*mol^-1))/((8.0*g)/(2.0*g*mol^-1)+(12.0*g)/(20.2*g*mol^-1))=0.129#....

And of course #chi_(H_2)+chi_(Ne)=1# as is absolutely required for a binary mixture of gases. I think the question also wanted you to calculate #P_"Total"#, and #P_"partial pressures..."#

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