What is the mole fraction of solute in a 3.37 #m# aqueous solution?

1 Answer
Jun 7, 2018

Answer:

#chi_"solute"-=0.0572#

Explanation:

We gots a solute that has a MOLAL concentration of #3.37*mol*kg^-1#...and so in #1*kg# of WATER there are #3.37*mol#...

Now #chi_"solute"="moles of solute"/"total mole in solution"#

#(3.37*mol)/(3.37*mol+(1000*g)/(18.01*g*mol^-1))=0.0572#

What is #chi_"water"#?