# What is the mole fraction of solute in a 3.37 m aqueous solution?

Jun 7, 2018

${\chi}_{\text{solute}} \equiv 0.0572$

#### Explanation:

We gots a solute that has a MOLAL concentration of $3.37 \cdot m o l \cdot k {g}^{-} 1$...and so in $1 \cdot k g$ of WATER there are $3.37 \cdot m o l$...

Now ${\chi}_{\text{solute"="moles of solute"/"total mole in solution}}$

$\frac{3.37 \cdot m o l}{3.37 \cdot m o l + \frac{1000 \cdot g}{18.01 \cdot g \cdot m o {l}^{-} 1}} = 0.0572$

What is ${\chi}_{\text{water}}$?