# What is the molecular formula of a compound that has 44.44% carbon, 3.73% hydrogen, and 51.83% nitrogen?

In $100$ $g$ of stuff, there are $\frac{44.44 \cdot g \cdot C}{12.011 \cdot g \cdot m o {l}^{-} 1} = 3.66 \cdot m o l$, and $\frac{3.73 \cdot g \cdot H}{1.00794 \cdot g \cdot m o {l}^{-} 1} = 3.71 \cdot m o l$, and $\frac{51.83 \cdot g \cdot N}{14.01 \cdot g \cdot m o {l}^{-} 1} = 3.70 \cdot m o l$.
Thus the empirical formula is $C H N$. The molecular formula is some multiple of $C H N$, but we don't know what it is on the basis of these data.