# What is the molecular formula of a compound with a molar mass of 180.2 grams/mole and the empirical formula CH_2O?

Feb 9, 2016

Thus $\text{MOLECULAR FORMULA}$ $=$ $\left(\text{EMPIRICAL FORMULA}\right) \times n$.
So $180.2 \cdot g \cdot m o {l}^{-} 1 = n \times \left(12.011 + 2 \times 1.00794 + 15.999\right) \cdot g \cdot m o {l}^{-} 1 = 30 \times n$.
$n = 6$, and $\text{MOLECULAR FORMULA}$ $=$ $6 \times \left(C {H}_{2} O\right) = {C}_{6} {H}_{12} {O}_{6}$.