# What is the moment of inertia of a pendulum with a mass of 2 kg that is 3 m from the pivot?

The Inertia is $I = 18 k g {m}^{2}$
$I = m \cdot {r}^{2}$
$I = \left(2 \cdot {3}^{2}\right) k g {m}^{2}$
$I = 18 k g {m}^{2}$