What is the moment of inertia of a pendulum with a mass of 2 kg that is 5 m from the pivot?

Apr 24, 2017

50 $k g {m}^{2}$
$I = m {r}^{2} = \left(2\right) {\left(5\right)}^{2} =$50 $k g \cdot {m}^{2}$