Question

What is the moment of inertia of a pendulum with a mass of `2 kg` that is `7 m` from the pivot?

Answer 1

The answer is `I = mr^2` = 98 `kgm^2`

Explanation:

Assuming you are not being asked to derive the moment of inertia of the pendulum, I will state without proof that this is

`I = mr^2`

where `m` is the mass hanging from the pendulum and `r` is the distance from the pivot to the centre of the mass.

With your values, this comes to

`I = 2 xx 7^2` = 98 `kgm^2`