What is the moment of inertia of a pendulum with a mass of #2 kg# that is #7 m# from the pivot?

1 Answer
Dec 18, 2016

Answer:

The answer is #I = mr^2# = 98 #kgm^2#

Explanation:

Assuming you are not being asked to derive the moment of inertia of the pendulum, I will state without proof that this is

#I = mr^2#

where #m# is the mass hanging from the pendulum and #r# is the distance from the pivot to the centre of the mass.

With your values, this comes to

#I = 2 xx 7^2# = 98 #kgm^2#