# What is the moment of inertia of a pendulum with a mass of 3 kg that is 11 m from the pivot?

Jul 17, 2017

The moment of inertia is $= 363 k g {m}^{2}$

#### Explanation:

The mass of the pendulum is

$m = 3 k g$

The distance from the pivot is

$r = 11 m$

The moment of inertia is

$I = m {r}^{2} = 3 \cdot {11}^{2}$

$= 363 k g {m}^{2}$