# What is the moment of inertia of a pendulum with a mass of 3 kg that is 3 m from the pivot?

Apr 10, 2018

$27 \setminus {\text{kg m}}^{2}$

#### Explanation:

The moment of inertia of a simple pendulum is given by:

$I = m {r}^{2}$

• $m$ is the mass of the bob in kilograms

• $r$ is the distance of the bob from the pivot in meters

And so, we get:

I=3 \ "kg"*(3 \ "m")^2

$= 3 \setminus {\text{kg"*9 \ "m}}^{2}$

$= 27 \setminus {\text{kg m}}^{2}$