# What is the moment of inertia of a pendulum with a mass of 3 kg that is 9 m from the pivot?

Mar 17, 2018

$243 \setminus {\text{kg m}}^{2}$

#### Explanation:

Moment of inertia of a simple pendulum is given by:

$I = m {r}^{2}$

where $m$ is the mass of the pendulum in kilograms, $r$ is the distance of the pendulum from the pivot in meters.

Plugging in the given values, we get

I=3 \ "kg"*(9 \ "m")^2

$= 3 \setminus {\text{kg"*81 \ "m}}^{2}$

$= 243 \setminus {\text{kg m}}^{2}$