# What is the moment of inertia of a pendulum with a mass of 4 kg that is 14 m from the pivot?

Feb 23, 2017

The moment of inertia is $= 784 k g {m}^{2}$

#### Explanation:

The moment of inertia $I$ is

$I = m {r}^{2}$

$= 4 \cdot {14}^{2}$

$= 784 k g {m}^{2}$