# What is the moment of inertia of a pendulum with a mass of 4 kg that is 5 m from the pivot?

$I = 100 k g {m}^{2}$
The moment of inertia for a point mass is $I = m {r}^{2}$
So it is $I = m {r}^{2} = 4 \cdot 25 = 100 k g {m}^{2}$