# What is the moment of inertia of a pendulum with a mass of 4 kg that is 5 m from the pivot?

Jul 18, 2017

#### Answer:

$I = 100 k g {m}^{2}$

#### Explanation:

The moment of inertia for a point mass is $I = m {r}^{2}$

So it is $I = m {r}^{2} = 4 \cdot 25 = 100 k g {m}^{2}$