Question

What is the moment of inertia of a pendulum with a mass of `5 kg` that is `1 m` from the pivot?

Answer 1

The moment of inertia is `5 kg*m^2`.

Explanation:

The formula for moment of inertia is `I = M*R^2`. Therefore the moment of inertia of this pendulum is

`I = M*R^2 = 5 kg * (1 m)^2 = 5 kg*m^2`

I hope this helps,
Steve