# What is the moment of inertia of a pendulum with a mass of 5 kg that is 1 m from the pivot?

Apr 10, 2018

The moment of inertia is $5 k g \cdot {m}^{2}$.

#### Explanation:

The formula for moment of inertia is $I = M \cdot {R}^{2}$. Therefore the moment of inertia of this pendulum is

$I = M \cdot {R}^{2} = 5 k g \cdot {\left(1 m\right)}^{2} = 5 k g \cdot {m}^{2}$

I hope this helps,
Steve