Question

What is the moment of inertia of a pendulum with a mass of `5 kg` that is `10 m` from the pivot?

Answer 1

The moment of inertia is `=500kgm^2`

Explanation:

The mass of the pendulun is `m=5kg`

The distance from the pivot is `r=10m`

The moment of inertia is

`I=mr^2=5*10^2=500kgm^2`