# What is the moment of inertia of a pendulum with a mass of 5 kg that is 10 m from the pivot?

Jul 23, 2017

The moment of inertia is $= 500 k g {m}^{2}$

#### Explanation:

The mass of the pendulun is $m = 5 k g$

The distance from the pivot is $r = 10 m$

The moment of inertia is

$I = m {r}^{2} = 5 \cdot {10}^{2} = 500 k g {m}^{2}$