# What is the moment of inertia of a pendulum with a mass of 5 kg that is 2 m from the pivot?

Apr 30, 2018

$20 \setminus {\text{kg m}}^{2}$

#### Explanation:

Moment of inertia of a simple pendulum is given by,

$I = m {r}^{2}$

• $m$ is the mass of the pendulum

• $r$ is the distance of the pendulum from the pivot point

And so, plugging in our given values, we get,

I=5 \ "kg"*(2 \ "m")^2

$= 5 \setminus {\text{kg"*4 \ "m}}^{2}$

$= 20 \setminus {\text{kg m}}^{2}$