What is the moment of inertia of a pendulum with a mass of #5 kg# that is #2 m# from the pivot?

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Answer 1 · 2018-04-30T01:14:14

#20 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by,

#I=mr^2#

#m# is the mass of the pendulum

#r# is the distance of the pendulum from the pivot point

And so, plugging in our given values, we get,

#I=5 \ "kg"*(2 \ "m")^2#

#=5 \ "kg"*4 \ "m"^2#

#=20 \ "kg m"^2#