# What is the moment of inertia of a pendulum with a mass of 5 kg that is 5 m from the pivot?

Dec 17, 2015

$125 {\text{ ""kg.m}}^{2}$

#### Explanation:

We can consider the mass $m$ to be a point mass which is at a distance $r$ from the pivot.

The moment of inertia $I$ is given by:

$I = m {r}^{2}$

$\therefore I = 5 \times {5}^{2} = 125 {\text{ ""kg.m}}^{2}$