What is the moment of inertia of a pendulum with a mass of #5 kg# that is #6 m# from the pivot?

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Answer 1 · 2018-05-04T12:00:32

#180 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by:

#I=mr^2#

#m# is the mass of the object

#r# is the distance of the object from the pivot

And so, plugging in our given values, we get,

#I=5 \ "kg"*(6 \ "m")^2#

#=5 \ "kg"*36 \ "m"^2#

#=180 \ "kg m"^2#