# What is the moment of inertia of a pendulum with a mass of 5 kg that is 8 m from the pivot?

Feb 13, 2016

$320 k g . {m}^{2}$

#### Explanation:

Assuming simple pendulum, where the mass and dimensions are relatively small compared to the mass of the bob, we may use the approximation :

$I = M {R}^{2}$

$= 5 \times {8}^{2}$

$= 320 k g . {m}^{2}$.