Question

What is the moment of inertia of a pendulum with a mass of `6 kg` that is `8 m` from the pivot?

Answer 1

The moment of inertia is `=384kgm^2`

Explanation:

The moment of inertia is

`I=mr^2`

The mass `m=6kg`

Distance from pivot `r=8m`

Therefore,

`I=6*8^2=384kgm^2`