# What is the moment of inertia of a pendulum with a mass of 6 kg that is 9 m from the pivot?

May 21, 2017

The moment of inertia is $= 486 k g {m}^{2}$

#### Explanation:

The moment of inertia is

$I = m {r}^{2}$

The mass is $m = 6 k g$

The distance from the pivot is $r = 9 m$

The moment of inertia is

$I = m {r}^{2} = 6 \cdot {\left(9\right)}^{2} = 486 k g {m}^{2}$