# What is the moment of inertia of a pendulum with a mass of 7 kg that is 1 m from the pivot?

Jun 8, 2017

The moment of inertia is $= 7 k g {m}^{2}$

#### Explanation:

We assume that it is a point mass.

The moment of inertia is

$I = m {r}^{2}$

The mass is $m = 7 k g$

The distance is $r = 1 m$

The moment of inertia is

$I = m {r}^{2} = 7 \cdot {1}^{2} = 7 k g {m}^{2}$